3.10.69 \(\int \frac {1}{(c x)^{13/2} (a+b x^2)^{3/4}} \, dx\) [969]

3.10.69.1 Optimal result

Integrand size = 19, antiderivative size = 157 \[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}+\frac {20 b \sqrt [4]{a+b x^2}}{77 a^2 c^3 (c x)^{7/2}}-\frac {40 b^2 \sqrt [4]{a+b x^2}}{77 a^3 c^5 (c x)^{3/2}}+\frac {80 b^{7/2} \left (1+\frac {a}{b x^2}\right )^{3/4} (c x)^{3/2} \operatorname {EllipticF}\left (\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ),2\right )}{77 a^{7/2} c^8 \left (a+b x^2\right )^{3/4}} \]

output

-2/11*(b*x^2+a)^(1/4)/a/c/(c*x)^(11/2)+20/77*b*(b*x^2+a)^(1/4)/a^2/c^3/(c* 
x)^(7/2)-40/77*b^2*(b*x^2+a)^(1/4)/a^3/c^5/(c*x)^(3/2)+80/77*b^(7/2)*(1+a/ 
b/x^2)^(3/4)*(c*x)^(3/2)*(cos(1/2*arccot(x*b^(1/2)/a^(1/2)))^2)^(1/2)/cos( 
1/2*arccot(x*b^(1/2)/a^(1/2)))*EllipticF(sin(1/2*arccot(x*b^(1/2)/a^(1/2)) 
),2^(1/2))/a^(7/2)/c^8/(b*x^2+a)^(3/4)
 

3.10.69.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.01 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.36 \[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=-\frac {2 x \left (1+\frac {b x^2}{a}\right )^{3/4} \operatorname {Hypergeometric2F1}\left (-\frac {11}{4},\frac {3}{4},-\frac {7}{4},-\frac {b x^2}{a}\right )}{11 (c x)^{13/2} \left (a+b x^2\right )^{3/4}} \]

input

Integrate[1/((c*x)^(13/2)*(a + b*x^2)^(3/4)),x]
 

output

(-2*x*(1 + (b*x^2)/a)^(3/4)*Hypergeometric2F1[-11/4, 3/4, -7/4, -((b*x^2)/ 
a)])/(11*(c*x)^(13/2)*(a + b*x^2)^(3/4))
 

3.10.69.3 Rubi [A] (warning: unable to verify)

Time = 0.33 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.15, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.421, Rules used = {264, 264, 264, 266, 768, 858, 807, 229}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx\)

\(\Big \downarrow \) 264

\(\displaystyle -\frac {10 b \int \frac {1}{(c x)^{9/2} \left (b x^2+a\right )^{3/4}}dx}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 264

\(\displaystyle -\frac {10 b \left (-\frac {6 b \int \frac {1}{(c x)^{5/2} \left (b x^2+a\right )^{3/4}}dx}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 264

\(\displaystyle -\frac {10 b \left (-\frac {6 b \left (-\frac {2 b \int \frac {1}{\sqrt {c x} \left (b x^2+a\right )^{3/4}}dx}{3 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{3 a c (c x)^{3/2}}\right )}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 266

\(\displaystyle -\frac {10 b \left (-\frac {6 b \left (-\frac {4 b \int \frac {1}{\left (b x^2+a\right )^{3/4}}d\sqrt {c x}}{3 a c^3}-\frac {2 \sqrt [4]{a+b x^2}}{3 a c (c x)^{3/2}}\right )}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 768

\(\displaystyle -\frac {10 b \left (-\frac {6 b \left (-\frac {4 b (c x)^{3/2} \left (\frac {a}{b x^2}+1\right )^{3/4} \int \frac {1}{\left (\frac {a}{b x^2}+1\right )^{3/4} (c x)^{3/2}}d\sqrt {c x}}{3 a c^3 \left (a+b x^2\right )^{3/4}}-\frac {2 \sqrt [4]{a+b x^2}}{3 a c (c x)^{3/2}}\right )}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 858

\(\displaystyle -\frac {10 b \left (-\frac {6 b \left (\frac {4 b (c x)^{3/2} \left (\frac {a}{b x^2}+1\right )^{3/4} \int \frac {1}{\sqrt {c x} \left (\frac {a x^2 c^4}{b}+1\right )^{3/4}}d\frac {1}{\sqrt {c x}}}{3 a c^3 \left (a+b x^2\right )^{3/4}}-\frac {2 \sqrt [4]{a+b x^2}}{3 a c (c x)^{3/2}}\right )}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 807

\(\displaystyle -\frac {10 b \left (-\frac {6 b \left (\frac {2 b (c x)^{3/2} \left (\frac {a}{b x^2}+1\right )^{3/4} \int \frac {1}{\left (\frac {a x c^3}{b}+1\right )^{3/4}}d(c x)}{3 a c^3 \left (a+b x^2\right )^{3/4}}-\frac {2 \sqrt [4]{a+b x^2}}{3 a c (c x)^{3/2}}\right )}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

\(\Big \downarrow \) 229

\(\displaystyle -\frac {10 b \left (-\frac {6 b \left (\frac {4 b^{3/2} (c x)^{3/2} \left (\frac {a}{b x^2}+1\right )^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arctan \left (\frac {\sqrt {a} c^2 x}{\sqrt {b}}\right ),2\right )}{3 a^{3/2} c^4 \left (a+b x^2\right )^{3/4}}-\frac {2 \sqrt [4]{a+b x^2}}{3 a c (c x)^{3/2}}\right )}{7 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{7 a c (c x)^{7/2}}\right )}{11 a c^2}-\frac {2 \sqrt [4]{a+b x^2}}{11 a c (c x)^{11/2}}\)

input

Int[1/((c*x)^(13/2)*(a + b*x^2)^(3/4)),x]
 

output

(-2*(a + b*x^2)^(1/4))/(11*a*c*(c*x)^(11/2)) - (10*b*((-2*(a + b*x^2)^(1/4 
))/(7*a*c*(c*x)^(7/2)) - (6*b*((-2*(a + b*x^2)^(1/4))/(3*a*c*(c*x)^(3/2)) 
+ (4*b^(3/2)*(1 + a/(b*x^2))^(3/4)*(c*x)^(3/2)*EllipticF[ArcTan[(Sqrt[a]*c 
^2*x)/Sqrt[b]]/2, 2])/(3*a^(3/2)*c^4*(a + b*x^2)^(3/4))))/(7*a*c^2)))/(11* 
a*c^2)
 

3.10.69.3.1 Defintions of rubi rules used

rule 229

Int[((a_) + (b_.)*(x_)^2)^(-3/4), x_Symbol] :> Simp[(2/(a^(3/4)*Rt[b/a, 2]) 
)*EllipticF[(1/2)*ArcTan[Rt[b/a, 2]*x], 2], x] /; FreeQ[{a, b}, x] && GtQ[a 
, 0] && PosQ[b/a]
 

rule 264

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( 
m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c 
^2*(m + 1)))   Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p 
}, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
 

rule 266

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De 
nominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) 
^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I 
ntBinomialQ[a, b, c, 2, m, p, x]
 

rule 768

Int[((a_) + (b_.)*(x_)^4)^(-3/4), x_Symbol] :> Simp[x^3*((1 + a/(b*x^4))^(3 
/4)/(a + b*x^4)^(3/4))   Int[1/(x^3*(1 + a/(b*x^4))^(3/4)), x], x] /; FreeQ 
[{a, b}, x]
 

rule 807

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m 
+ 1, n]}, Simp[1/k   Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, 
x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
 

rule 858

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Subst[Int[(a + 
b/x^n)^p/x^(m + 2), x], x, 1/x] /; FreeQ[{a, b, p}, x] && ILtQ[n, 0] && Int 
egerQ[m]
 

3.10.69.4 Maple [F]

\[\int \frac {1}{\left (c x \right )^{\frac {13}{2}} \left (b \,x^{2}+a \right )^{\frac {3}{4}}}d x\]

input

int(1/(c*x)^(13/2)/(b*x^2+a)^(3/4),x)
 

output

int(1/(c*x)^(13/2)/(b*x^2+a)^(3/4),x)
 

3.10.69.5 Fricas [F]

\[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=\int { \frac {1}{{\left (b x^{2} + a\right )}^{\frac {3}{4}} \left (c x\right )^{\frac {13}{2}}} \,d x } \]

input

integrate(1/(c*x)^(13/2)/(b*x^2+a)^(3/4),x, algorithm="fricas")
 

output

integral((b*x^2 + a)^(1/4)*sqrt(c*x)/(b*c^7*x^9 + a*c^7*x^7), x)
 

3.10.69.6 Sympy [F(-1)]

Timed out. \[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=\text {Timed out} \]

input

integrate(1/(c*x)**(13/2)/(b*x**2+a)**(3/4),x)
 

output

Timed out
 

3.10.69.7 Maxima [F]

\[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=\int { \frac {1}{{\left (b x^{2} + a\right )}^{\frac {3}{4}} \left (c x\right )^{\frac {13}{2}}} \,d x } \]

input

integrate(1/(c*x)^(13/2)/(b*x^2+a)^(3/4),x, algorithm="maxima")
 

output

integrate(1/((b*x^2 + a)^(3/4)*(c*x)^(13/2)), x)
 

3.10.69.8 Giac [F]

\[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=\int { \frac {1}{{\left (b x^{2} + a\right )}^{\frac {3}{4}} \left (c x\right )^{\frac {13}{2}}} \,d x } \]

input

integrate(1/(c*x)^(13/2)/(b*x^2+a)^(3/4),x, algorithm="giac")
 

output

integrate(1/((b*x^2 + a)^(3/4)*(c*x)^(13/2)), x)
 

3.10.69.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1}{(c x)^{13/2} \left (a+b x^2\right )^{3/4}} \, dx=\int \frac {1}{{\left (c\,x\right )}^{13/2}\,{\left (b\,x^2+a\right )}^{3/4}} \,d x \]

input

int(1/((c*x)^(13/2)*(a + b*x^2)^(3/4)),x)
 

output

int(1/((c*x)^(13/2)*(a + b*x^2)^(3/4)), x)